How do you do this problem ?

Question

Simplify each complex fraction.

(3) / (5y) + 8

-----------------
( 3) / (5y) - 8

Answer 1

I assume you have the actual problem as

[3/5y +8] / [3/5y - 8]; if this is wrong the simplification is done as the numerator and as the denominator simplification

lets simplify this

the numerator is (3 + 8*5y) / 5y

the denominator is (3-8*5y) / 5y

now ratioing numerator / denominator, and simplifing and multiplying by 5y/5y you end up with

(3 +40 y)/(3-40y)

Answer 2

Just I will multiply the numerator & denominator both by 5y:

[3/(5y) + 8]/[3/(5y) - 8] = (3 + 40y)/(3 - 40y).

And that's it, as it can't be simplified any more.

Answer 3

Deal with the fractions above and below the main fraction first.... but before that:

Does it look like
(3/5y) +8
--------------
(3/5y) - 8

OR

3 / (5y +8)
--------------
3 / (5y -8)

?

Answer 4

The +8 is not in the denominator, I hope.
=(3+40y)/5y divided by (3-40y)/5y
cancel ot 5y
(3+40y)/(3-40y)

Answer 5

Why is it that each of the 500 questions you have asked are titled "How do you do this problem?"

Answer 6

take the conjigat