Suppose we move 9 times further from a star. How many times fainter will it appear?
2007-08-03 07:10:36 · 5 answers · asked by dothedip 1 in Science & Mathematics ➔ Astronomy & Space
I agree with 1/81 st as bright as there is an inverse square law for brightness. A slightly better question to ask would be if we moved ten times as far away from a star, what would the effect be. Plainly 1/100 th as bright and that is exactly 5 magnitudes dimmer.
2007-08-03 07:21:45 · answer #1 · answered by Anonymous · 0⤊ 1⤋
The inverse square law will yield the light intensity per unit area. However, the way that brightness appears to us is logarithmic, not linear. That is why the scale of apparent magnitude used in astronomy is logarithmic, with a base of 2.512. For every increase in magnitude, the brightness drops by 1/2.512
2007-08-03 14:29:33 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Inverse square law
I/Io = d^-2 = 9^-2 = 81^1
2007-08-03 14:17:00 · answer #3 · answered by GTB 7 · 0⤊ 0⤋
1/81 as bright
2007-08-03 14:13:46 · answer #4 · answered by alints_2000 4 · 0⤊ 0⤋
Light travels in 3-D from an object. Shoudn't it be the inverse cube law?
2007-08-03 14:18:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋