There's a game: I say a number from 1-6, then you say one from 1-6, and it goes back and forth, and we keep track of the sum. The person who makes the sum reach 50 wins. How can you ensure you always win?
2007-08-02 21:45:24 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If you are first, choose the number 1, because 50 is divisible by 7 with the remainder 1, and each time your opponent increase by a number n between 1 and 6, you can increase by 7-n because 7-n is an integer between 1 and 6.
1,x,8,x,15,x,22,x,29,x,36,x,43,x,50
2007-08-02 21:53:04 · answer #1 · answered by Amit Y 5 · 2⤊ 1⤋
The usual game is the first one to reach 50 loses. To ensure you always win in this game, whatever number your opponent call, you just add another number so that the two numbers add up to seven. Seven times seven is forty nine, thus the other party will be the one to reach 50.
2007-08-03 04:59:15 · answer #2 · answered by Kelvin 1 · 0⤊ 1⤋