If the earth's circumference is 24,800 miles, what is the linear velocity of a person standing on the equator in a span of 24 hours?
2007-08-02 18:56:54 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
C = 2 π r
r = C / 2π = 24800 / 2π
Angular velocity = w , say
w = 2π / 24 radians / hour
linear velocity = v miles / hour
v = w r
v = (2π / 24) x (24800 / 2π) miles per hour
v = 24800 / 24 miles per hour
V = 1033 . 3 miles per hour (to 1 dec. place)
2007-08-02 19:27:37 · answer #1 · answered by Como 7 · 1⤊ 0⤋
The person will travel 24800 miles per day, so the linear velocity is 24800/24 = 1033.33.. miles per hour, or if you prefer 24800/86400 = 1033.33../3600 = 0.287.. mile per second.
There is no difference whether the movement is straight-lined or not and no need to involve trigonometry .
2007-08-03 02:08:48 · answer #2 · answered by Duke 7 · 0⤊ 0⤋
wow.
i've nevr done trigonometry before
haha
the person above me just divided it
that seems easy enough
but the question sure sounded hard
2007-08-03 02:03:43 · answer #3 · answered by vennysweetgirl21 3 · 0⤊ 0⤋
24800/24
about 1034 mph
2007-08-03 02:02:32 · answer #4 · answered by jim 3 · 0⤊ 0⤋