40%<------>300 sec
100%<---->(100/40) x 300sec
= (5 / 2) x 300 sec
= 5 x 150 sec
= 750 sec
= 12 min 30 sec
2007-08-08 07:47:46
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answer #1
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answered by Como 7
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It has checked 40% in 300 Seconds
It needs to check another 60%
The ammount of time it will take to finish is (60/40) X 300 Seconds = 450 Seconds.
*Pssst... 750 Seconds is the entire process
2007-08-03 00:22:00
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answer #2
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answered by Brown Knight 2
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x total no of files
t total no of seconds
.40 x / 300 = x / t rate of scanner
x will cancel out in the equation
t = 300/.40 = 750 secs
2007-08-07 21:08:47
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answer #3
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answered by Anonymous
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40 % in 300s
So, 1% in 300s/40 = (30/4)s
=> 100% in (30 x 100)/4 = 30 x 25 = 750s
So, it will check all files in 12mins and 30 secs
2007-08-03 06:12:36
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answer #4
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answered by Nishit 3
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750 seconds
Set up a proportion. When will it check 100% of the files
40 / 300 = 100 / n
300*100 = 40 * n
30000 = 40n
30000 / 40 = n
750 = n
2007-08-03 00:13:51
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answer #5
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answered by Jeƒƒ Lebowski 6
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40% of the files scanned in 300 sec.
1% of the files would have taken = 300/40=7.5 sec.
100% of the files would take =7.5*100=750 sec.
=12 mins. 30 sec.
2007-08-03 00:13:31
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answer #6
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answered by Jain 4
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300*(100/40) = 750 s
2007-08-03 00:13:10
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answer #7
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answered by bilbo 3
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Let x = no. of seconds to check all files.
Equation:
0.4x = 300 seconds
x = 750 seconds
Answer: 12 1/2 minutes or 12 minutes & 30 seconds.
2007-08-08 04:50:28
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answer #8
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answered by Jun Agruda 7
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you divide 300 by 40. which equals 7.5. This means that for ever percent to be checked, it takes 7.5 seconds.
Then to find how many seconds it takes to check all the files you multiply 7.5 by 100 (percent) which equals 750. So it takes 750 seconds to check them all.
2007-08-03 00:15:39
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answer #9
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answered by sara w 2
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300 /.4 = 750 secs.
2007-08-03 00:31:57
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answer #10
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answered by sheik_sebir 4
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