how many dies would it take to roll 673?

Answer 1

113. roll 112 6's and roll one 1

Answer 2

I assume you want a distributed answer since the odds are of getting any number in 6.

First, add up all the numbers on the die. 6 + 5 + 4 + 3 + 2 + 1 = 21.

673 / 21 = 32, R1. So 21 * 32 = 672.

So this gives us 32 of each except we need an additional 1 roll.

32 - 6
32 - 5
32 - 4
32 - 3
32 - 2
33 - 1

So it will take approximately 193 rolls. Of course, this could be a trick question. You could roll all of this on just a single die with enough turns.

Answer 3

Somewhere between 113 and 673.

Answer 4

You could have someone make you a solid of extraordinary facets, and just use that as a massive die.

So, my answer as a machinist, is one.