Asample of SO2 gas which weighs 0.81 grams has a volume of 1.20 liters when collected at 25 degrees celisus.?

Question

what would be the pressure of the gas sample?

Answer 1

0.81 grams of SO2 has volume of 1.20liters.

As per the gas laws 64 gms of SO2 has volume of 22.4 liters at NTP ;
So 0.81 grams of SO2 should have volume of
= (0.81/64)*22.4 litres;
=0.2835 Lts.
But ,the observed volume at 25deg C = 1.20lts

So P1V1 = P2V2

or 1*0.2835 = P2 *1.2

or P2 = 0.2835/1.2 ;
or P2 = 0.236 atm.

Answer 2

Using the ideal gas law, PV = nRT, just substitute everything in. You are looking for P, so rearrange the equation to say P = nRT/V

S02 has a molar mass of about 64.1 grams/mol, so you have n = 0.0126 moles of SO2.

R is your gas constant: 0.0821 L atm/ K mol

25 degrees celsius is equal to 298 K, so T = 298 K

V = 1.20 L

When you substitute it all, you get P = (0.0126)(0.0821)(298)/(1.20)

Just plug it into a calculator to get your final answer in atm's!

Answer 3

Since your ideal gas formula requires moles, convert your weight of SO2 to moles. Then you do the pV= nRT thing with p as your unknown, V=1.2 L, n= moles from above and R= 0.082 L-atm/mole-degK, and T= 298 deg K. Your answer will be in atm.