Agas sample has an original volume of 600 ml when collected at 720 mm and 35 degrees Celsius.?

Question

If a change is made in the gas temperature which causes the volume of the gas sample to become 520 ml at 1.00 atm,what is the new temperature?

Answer 1

V0 = 600 ml, p0=720 mm and T0 = 35 C

V1 = 520 ml, p1 = 1 atm = 760 mm

Now pV=nRT so nR = p0V0/T0

Then T1 = p1V1/(nR) = T0 * p1V1/(p0V0)

Answer 2

The Combined Gas Law.
P1 x V1 x T2 = P2 x V2 x T1.
720mmHg x 600mL x T2=760mmHg x 520mL x 35°C (308K).
T2 = (760 x 520 x 308) ÷ (720 x 600)
Final Temp. (T2) = 121,721,600 ÷ 432,000 = 281.8K
281.8K - 273 = 8.8°C

Answer 3

P1V1/T1=P2V2/T2
THAT'S THE EQUATION TO USE....PLUG AND CHUG