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2007-08-02 14:09:51 · 3 answers · asked by Jacesmom 2 in Science & Mathematics Mathematics

3 answers

3/x - 3 + 3/x +2 = (3 - 3x +3 +2x)/x = (6 - x)/x

2007-08-02 14:14:37 · answer #1 · answered by nyphdinmd 7 · 0 1

I'm assuming that you have two terms with denominators equal to x and two constant terms. That is, your expression is not

3/(x-3) + 3/(x+2) [If this is the expression you meant, it can also be simplied - please clarify]

For the expression as you have written it, you simply have a task of gathering like terms. I simply re-order the expression:

3/x + 3/x - 3 + 2

Remember, when adding fractions with like denominators, you simply add the numerator. You simply add the constants. The resulting expression is:

6/x -1

2007-08-02 21:18:57 · answer #2 · answered by Joe S 6 · 0 0

(3/x-3 )+ (3/x+2)
=(3(x+2)+3(x-3))/(x-3)(x+2)
=(3x+6+3x-9)/(x-3)(x+2)
=(6x-3)/(x-3)(x+2)
=3(2x-1)/(x-3)(x+2)

or

3/x-3 + 3/x+2
=6/x-1
=(6-x)/x

2007-08-02 21:25:15 · answer #3 · answered by yenchin 2 · 0 1

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