x^2 + 8x = -16
2007-08-02 07:32:05 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
leave answers in simplest radical form
2007-08-02 07:32:41 · update #1
rewrite as: x^2+8x+16=0
factor
(x+4)(x+4)=0
x=-4
2007-08-02 07:34:42 · answer #1 · answered by miggitymaggz 5 · 2⤊ 0⤋
I'll rewrite this as x^2 + 8x + 16 = 0, and then factor to (x + 4)^2 = 0, so the only solution is x = -4.
2007-08-02 07:35:18 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
x^2 + 8x +16=0
(x+4)(x+4)=0 ==> x+4 =0 or x+4= 0
so x = -4
2007-08-02 07:38:25 · answer #3 · answered by m_math 1 · 0⤊ 0⤋
x^2 + 8x + 16 = 0, so (x + 4)^2 = 0, and x+4 = 0, or x = -4.
2007-08-02 07:35:54 · answer #4 · answered by John V 6 · 0⤊ 0⤋
x^2 + 8x = -16
x^2 + 8x + 16 = 0
(x + 4)(x + 4) = 0 {easy to factor}
x = -4, x = -4
2007-08-02 07:37:51 · answer #5 · answered by kindricko 7 · 0⤊ 0⤋