from class c address192.168.3.0/24 which adress to configure three routers in diffferent locations?

Question

routers are in different locations and need to configure fast ethernet and serial interfaces and dynamic routing protocols

Answer 1

Unless you are running out of IP addresses, I would use a different 24 bit subnet for each location.

If 192.168.4.0/24 192.178.5.0/24 and 192.168.6.0/24 are not already used, then I would use those subnets for the remote offices and continue to use the 192.168.3.0/24 subnet in your office.

You can set aside small subnets for the serial ports so they will not interfere with dynamic routing protocols. You can create subnets such as
192.168.255.0/30
192.168.255.4/30
192.168.255.8/30
192.168.255.12/30
192.168.255.16/30
192.168.255.20/30
192.168.255.24/30
...

This will give you enough subnets for 64 T1 connections.
For each T1 connection, assign the serial port IP addresses to an address in the same subnet. Make sure that the subnet is defined properly on each serial port. There is no default gateway on these subnets, so the ip address other than the network address and the broadcast address are useable (subnet +1 and subnet + 2 are useable for the serial ports. For consistency, always assign the +1 address to the local serial port address and the +2 address to the remote serial port address).

In summary, the ethernet ports on the routers would have IP addresses in the subnets used for the remote offices. The serial ports on the routers would be in the small subnets in the 192.168.255.x/30 number ranges.

Answer 2

Man, that's a large/tough question. If you dont know the answer, Yahoo Answers is not the place to start looking.

I mean, you start getting into VLSM and CIDR and all kinds of stuff. It's way too complicated for anyone to explain here.

Essentially, use VLSM to sbunet the 192.168.3.0/24 network into three networks. If you desire to have all three networks to have the same amount of hosts, the first network number would be would be 192.168.3.0/26. The next network number would be 192.168.3.64/26. The next would be 192.168.3.128/26. The last would be 192.168.3.192/26. This creates 4 networks and you only need three. You can create three through more extensive planning, but this is all I can come up with with the info you provided. You would use one of the host addresses within the networks to assign to each routers ethernet interface. I would suggest 192.168.3.1/26, 192.168.3.65/26 and 192.168.3.129/26. The you have to get into route summarization. I assume you know that you are dealing with a private address and you need to have a public address to translate to. You would need three public address to assign to your serial ports. Then you would probably use PAT to translate the public addresses to you private ones.

As for your routing protocols, it's up to you and the type of network and environment you have set up.

Both subjects, IP addressing and routing protocols, are way too complicated to go into any depth.

In all reality, if you have to ask this question, you have no business trying to attempt this

Answer 3

192.169.x is your network address.

.0 is your host address.

Subnet 1 = 192.168.1.0/24
Subnet 2 = 192.168.2.0/24
Subnet 3 = 192.168.3.0/24

Each subnet can have host addresses from 1 to 254.

Your subnet mask is 255.255.255.0