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2007-08-02 06:08:41 · 3 answers · asked by sameerteacher01 1 in Science & Mathematics Physics

3 answers

♣ density w J/m^3 =W/V = (0.5/V)*C*U^2, where C is capacitance, W is energy of capacitor, V is volume betwixt plates, U is pot diff betwixt plates;
Sameer don’t spit into helping hand.

2007-08-02 07:11:56 · answer #1 · answered by Anonymous · 0 0

For a parallal plate capacitor of area A, seprated by d,

Capacitance,C=ε0A/d

If V is pd across the plates,energy stored is;

U=(1/2)CV²

=(1/2)(εAV²/d)

Volume of space bw the plates=A*d

Energy density=Energy/unit volume

=[(1/2)(εAV²/d)]/Ad

=(1/2)(εV²/d²)
V/d=E,electric intensity

Energy density=(1/2)εE²

2007-08-03 04:06:57 · answer #2 · answered by ♫♪sree♪♫ 3 · 0 0

Energy desnity is = 1/2e*E^2
where e = permittivity of media and E = electric field.

If there is a charge Q on the palte of the capacitor and the plate area is A, the then electric field is

E = Q/(eA ) energy density = Q^2/(eA^2)

2007-08-02 13:20:15 · answer #3 · answered by nyphdinmd 7 · 1 0

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