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A.f(0)>f(1) B. f(2)>f(1) C.f(1)>f(3)
f'(x)=(x-1)^2 and f(x) contains the origin.

2007-08-02 05:56:36 · 2 answers · asked by JYC 1 in Science & Mathematics Mathematics

2 answers

Integrating the last relation gives
f(x) = (x-1)³ /3 + C
Since f(x) contains the origin
0 = -1/3+C
f(x) = [(x-1)³ +1] / 3.
So
f(0) = 0, f(1) = 1/3, so statement A is false.
f(2) = 2/3, f(1) = 1/3, so statement B is true.
f(3) = 3, f(1) = 1/3, so statement C is false.

2007-08-02 07:31:54 · answer #1 · answered by steiner1745 7 · 1 0

Because f'(x) = "something squared",
f'(x) is non-negative and f(x) is monotoneously increasing.

For this reason f(0)

2007-08-02 06:38:08 · answer #2 · answered by Alexander 6 · 0 0

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