The length of a rectangle is 3 in. more than twice its width. If the perimeter of the rectangle is 36 in., find the width of the rectangle.
2007-08-02 04:40:11 · 4 answers · asked by trevor s 2 in Science & Mathematics ➔ Mathematics
Let l be the length and w the width. It is given that
l = 2w + 3 and 2l + 2w = 36 or l + w = 18
So, 2w + 3 = 18 - w = l
3w = 15
w = 5
l = 13
Width is 5 inches.
2007-08-02 04:45:32 · answer #1 · answered by Swamy 7 · 0⤊ 0⤋
Let l and w be the length and width of the rectangle respectively.
l=2w+3
2l+2w=36
2(2w+3)+2w=36
4w+6+2w=36
6w+6=36
6w=30
w=5
l=3+2(5)=13
check: perimeter=2l+2w=2(13)+2(5)=26+10=36
2007-08-02 11:51:43 · answer #2 · answered by cidyah 7 · 0⤊ 0⤋
This is another system of equations problem.
L= Length W=width
2L+2W=36 (perimeter)
L = 2W + 3 (3 more than twice the width)
Plug 'n' Chug
2007-08-02 11:46:29 · answer #3 · answered by Jake S 5 · 0⤊ 0⤋
p=2(L+w)
36=2(2w-3+w)-------------divid by2
18=3w-3
18+3=3w
21=3w
w=21/3=7
2007-08-02 11:45:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋