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What are the coordinates of the midpoint of the line segment whose endpoints are A(0, 2, 4) and B(-8, 2, -6)?

1. (8, 0, -10)
2. (0, 4, -24)
3. (-4, 2, -1)
4. (8, 4, -2)

2007-08-02 03:28:34 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

3. (-4,2,-1)

2007-08-02 03:34:16 · answer #1 · answered by Indian Primrose 6 · 0 0

0+-8=-8/2=-4
2+2 = 4/2 = 2
4+-6= -2/2 = -1

the midpoint is at (-4, 2,-1) 3

2007-08-02 03:39:24 · answer #2 · answered by Anonymous · 0 0

Very easy to solve. All you have to do is average out the coordinates of the 2 points.
M=((0-8)/2 , (2+2)/2 , (4-6)/2) = (-4,2,-1) =>3. is the correct answer

2007-08-02 03:36:43 · answer #3 · answered by Shadow 3 · 0 0

3. (-4, 2, -1)

x midpoint = (0 + (-8)) / 2 = -4
y midpoint = (2 + 2) / 2 = 2
z midpoint = (4 + (-6)) / 2 = -1

2007-08-02 03:32:27 · answer #4 · answered by Worm Brain 2 · 0 0

3.
just add the corresponding coordinates of the two endpoints and divide by 2 to get the midpoint

2007-08-02 03:36:35 · answer #5 · answered by shubham_nath 3 · 0 0

the answer is 3 , you find this taking the mean of each coordinate
ex for x (0-8)/2 =4

check that (-4,2,-1) is the good answer

2007-08-02 03:33:51 · answer #6 · answered by maussy 7 · 0 0

midpoint of a line segment on 3d space
(x1, y1, z1), (x2, y2, z2)
mid ( (x1+x2)/2, (y1+y2)/2, (z1+z2)/2 )
midpoint (0-8/2, 2+2/2, 4-6/2)
midpoint (-8/2, 4/2, -2/2)

midpoint
3. (-4, 2, -1)

2007-08-02 03:35:54 · answer #7 · answered by yeah_boy 2 · 0 0

x = (0-8)/2 = -4
y = (2+2)/2 = 2
z =(4-6)/2 = -1

answer 3. . .(- 4, 2, -1)

2007-08-02 03:37:06 · answer #8 · answered by CPUcate 6 · 0 0

to find the mid point we use the following formula

mid point = [ (x1+x2)/2, (y1+y2)/2,(z1+z2)/2 ]

from that we can see that the answer is 3

2007-08-02 03:36:48 · answer #9 · answered by tom t 2 · 0 0

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