I think you substitue it into the a, but adding 3 into the a number being divide has me thrown off.
2007-08-01 19:40:53 · 6 answers · asked by Keshawn 1 in Science & Mathematics ➔ Mathematics
f(a + 3) = [ 2(a + 3) + 5 ] / [ a + 3 + 2 ]
f(a + 3) = (2a + 11) / (a + 5)
2007-08-01 22:41:22 · answer #1 · answered by Como 7 · 0⤊ 0⤋
f(a+3) = [2(a+3) +5] / [a+3+2]
= 2a+6+5 / a+5
= 2a+11 /a+5
2007-08-01 19:43:46 · answer #2 · answered by sweet n simple 5 · 0⤊ 0⤋
You are almost there, what you do is plug in the a+3 for x:
2(a+3)+5 / (a+3) +2 =
2a+11 / a+5
And that would be your answer.
2007-08-01 19:43:50 · answer #3 · answered by AibohphobiA 4 · 0⤊ 0⤋
You simply put (a+3) in x
f(a+3)= 2(a+3) + 5/(a+3) + 2 =
= [2(a+3)^2]/(a+3) + 5/(a+3) + 2(a+3)/(a+3) =
= [2a^2+12a+18+5+2a+6]/(a+3) =
= (2a^2+14a+29)/(a+3) =
= 2(a+5)(a+2)/(a+3).
2007-08-01 19:51:52 · answer #4 · answered by jouliesk 1 · 0⤊ 0⤋
2(a+3) + 5 / (a+3) +2
= 2a + 6 + 5/(a+3) + 2
= 2a + 5/(a+3) + 8
i hope that's what you were looking for??
2007-08-01 19:52:21 · answer #5 · answered by apatel1488 2 · 0⤊ 0⤋
replace x with (a +3)
f(x) = 2 ( a + 3 ) + 5
--------------------
( a + 3 ) + 2
= 2a + 6 + 5
----------------
a + 5
= 2a + 11
-----------
a + 5
2007-08-01 19:54:12 · answer #6 · answered by charu b 2 · 0⤊ 0⤋