is it 5 to the power 7/4
2007-08-01 19:25:47 · 9 answers · asked by paavni 2 in Science & Mathematics ➔ Mathematics
= [ 5 [ 2 + 3 ] ³ ] ^ (1/4)
= (5 ^ 4) ^ (1/4)
= 5
2007-08-08 07:11:27 · answer #1 · answered by Como 7 · 1⤊ 0⤋
If the question is
evaluate: 5[(8 to the power1/3 + 27 to the power1/3)to the power3]to the power 1/4.
Then
8 to the power1/3 = 2
27 to the power1/3 =3
Hence the answer is 5[(2+3)^3]^1/4 =5*5^(3/4)= 5^(7/4)
If, however, the question is
evaluate: {5[(8 to the power1/3 + 27 to the power1/3)to the power3]} to the power 1/4.
The answer will be (5^4)^(1/4) = 5
2007-08-02 02:40:11 · answer #2 · answered by Debidas M 2 · 0⤊ 1⤋
5 ( 2 + 3)^3 = 5 *5^3 = 5^4
(5^4)^1/4 = 5^(4/4) = 5
2007-08-09 19:18:43 · answer #3 · answered by Anonymous · 0⤊ 1⤋
yes, it is 5 to the power 7/4
2007-08-10 01:36:03 · answer #4 · answered by sc 1 · 0⤊ 0⤋
5 [ [{ (2 to the power of 3)to the power of 1/3} {( 3 to the power of 3) to the power of 1/3}] to the power of 3]to the power of 1/4]
as 8 =2 to the power of 3 , and
9 = 3 to the power of 3
^ = sign of to the power
5 [ [2 +3 ] ^ 3 ] ^1/4]
5 [ 5 ] ^ 3/4
25 ^ 3/4
since 25 = 5 ^ 2
therefore ,
( 5 ^ 2 ) ^ 3/4 = 5 ^ (2 * 3/4 )
5 ^ 3/2
hope this solves ur problem!!!
2007-08-02 02:46:59 · answer #5 · answered by charu b 2 · 0⤊ 1⤋
Correct if the 5 in front is not under parentheses
otherwise it's 5
2007-08-02 02:29:20 · answer #6 · answered by AibohphobiA 4 · 0⤊ 0⤋
5[(8^1/3+27^1/3)^3]^1/4
5[{(2^3)^1/3+(3^3)^1/3}^3]^1/4
or5 [{2+3}^3]^1/4
or 5[5^3/4]
or( 5)^4/4.(5)^3/4
or 5^7/4---------------when bases are same powers are added.
2007-08-09 17:22:09 · answer #7 · answered by MAHAANIM07 4 · 0⤊ 1⤋
5[(8^(1/3)+27^(1/3))^(3)]^(1/4)
=5[(2+3)^3]^(1/4)
=5[5^(3/4)]
=5^(1+3/4)
=5^(7/4)
2007-08-02 02:34:21 · answer #8 · answered by niki einstien 2 · 0⤊ 0⤋
yes
2007-08-08 23:39:49 · answer #9 · answered by Jerik 2 · 0⤊ 1⤋