Difference of perfect squares:
(3a - 8b) (3a + 8b)
2007-08-01 17:56:49
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answer #1
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answered by Scarlet Manuka 7
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This is an example of sum and difference of two squares.
Just get the square root of each term
(3a - 8b) (3a + 8b)
2007-08-02 00:59:39
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answer #2
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answered by jepz 3
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9a^2 - 64b^2 = (3a + 8b) (3a - 8b)
2007-08-02 01:08:35
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answer #3
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answered by vlee1415 5
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9a^2 - 64b^2
=(3a + 8b) (3a - 8b)
2007-08-02 01:09:07
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answer #4
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answered by Simran 3
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9a^2-64b^2=(3a)^2-(8b)^2=(3a-8b)(3a+8b)
2007-08-02 11:59:50
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answer #5
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answered by Anonymous
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hi
you know (a+b)*(a-b)=a^2-b^2
so 9a^2=(3a)^2,
64b^2=(8b)^2
so (3a)^2-(8b)^2=(3a+8b)(3a-8b)
bye
2007-08-02 07:38:39
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answer #6
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answered by r s 3
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(3a + 8b) (3a - 8b)
2007-08-02 01:16:59
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answer #7
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answered by Anonymous
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isn't it (3a-8b)(3a+8b) ?
2007-08-02 00:58:31
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answer #8
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answered by IMPROCRASTINATING 2
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