Two airplanes leave New York at the same time and fly in opposite directions,
if one travels at 500 miles per hour and the other at 550 miles per
hour, how long will it take for them to be 4200 miles apart?
2007-08-01 17:32:13 · 7 answers · asked by Tazzzy 1 in Science & Mathematics ➔ Mathematics
Together they are traveling 500 + 550 = 1050 miles per hour apart.
To reach 4200 miles, it would take:
4200 / 1050 = 4 hours.
Checking the answer:
plane 1: 500 * 4 = 2000 miles away
plane 2: 550 * 4 = 2200 miles away in the opposite direction
combined distance = 2000 + 2200 = 4200 miles
2007-08-01 17:42:53 · answer #1 · answered by McFate 7 · 0⤊ 1⤋
Rate of separation is 550 + 500 = 1050 mph
distance = rate * time so
time = 4200/1050 = 4 hr
2007-08-01 17:48:45 · answer #2 · answered by fjblume2000 2 · 0⤊ 0⤋
Plane 1
d = 500 t
Plane 2
d = 550 t
500 t + 550 t = 4200
1050 t = 4200
t = 420 / 105 = 84 / 21 = 4
Time = 4 hours
2007-08-01 23:23:34 · answer #3 · answered by Como 7 · 1⤊ 0⤋
Two planes, one travelling at 500mph and the other at 550mph, are travelling a combined total of 1050mph. Divide 4200 by 1050, and you get 4. 4 hours.
2007-08-01 17:43:40 · answer #4 · answered by kaadish 5 · 0⤊ 0⤋
For increasing cubic binomials the final formulation is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D
2016-10-01 05:48:49 · answer #5 · answered by merkl 4 · 0⤊ 0⤋
solution:
t=time
500t+550t=4200
so, t=4hours
i am a Chinese,i can not use English skillfully.but I think u can understand.
2007-08-01 17:51:05 · answer #6 · answered by kwowhoo 1 · 0⤊ 0⤋
What grade of algerbra is that? Lol either im behind or thats way above my grade :D
2007-08-01 17:42:09 · answer #7 · answered by Ashley 2 · 0⤊ 0⤋