Algebra word problem!?

Question

Barry can do a certain job in 4 hours, whereas it takes Mike 6 hours to do
the same job. How long would it take them to do the job working together?

Answer 1

Barry can do 1/4 of the job per hour, Mike can do 1/6 of the job per hour, so together they can do 1/4 + 1/6 = 3/12 + 2/12 = 5/12 of the job per hour. So they can do the job in 12/5 of an hour, which is 144 minutes, or 2 hours and 24 minutes!

Answer 2

Barry works at the rate of .25 job per hr
Mike works at the rate of 1/6 job per hr
Together work at the rate of (1/4 +1/6) job per hr or 10/24 job per hr

completion time is 24/10 or 2.4 hours

Answer 3

The basic equation:
Output = SUM (output/hr) * hrs
To evaluate the inputs, Barry's output/hr = job/4
Mike's output/hr=job/6
Time for both to do a job=T
1 job =[ job/4+job/6]*T
job = 5 job/12 * T
and T = 12/5 hours (2.4 hrs)
You would do well to remember the equation, since almost all problems of this sort can be handled with it.

Answer 4

4+6=10 then 10/2=5 (average) divided by 2 (person)
5 /2= 2.5
the answer is 2 and 1/2 hours.

Answer 5

Let the quantity of work be "W"
Bary can do the job in 4hrs
The quantity of job Barry can do in one hour = W/4
Mike can do the job in 6 hrs
The quantity of job Mike can do in one hour= W/6
The total work done by both in one hour=W/4 + W/6
. . . . . . . . . . . . . . . . . . = 5W / 12
Hence the time taken by both together to complete the job =
. . . . . . . . . . . W / (5W/12) = 12/5 hours= 2 hrs 24 min.....Ans.
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . .==========

Answer 6

1/x = 1/4 + 1/6

or x = (4*6)/(4+6) = 24/10 = 2.4 hours or 2 hours and 24 min

Answer 7

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