What will it cost to cover a rectangular floor that measures 40 by 50 feet with square tiles that measure 2 feet on each side if a package of 10 tiles costs $13 per package?
be sure to work out
2007-08-01 16:14:21 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Area = 40 x 50 ft = 2000 sq ft
each tiles coveres 2x2 = 4 sqft
so you need 2000/4 = 500 tiles
1 package has 10 tiles, so you need 500/10 = 50 packages
at $13/package
50 packages costs $13 x 50 = $650
so Material cost = $650 + sales Tax
+ labor costs
2007-08-01 16:20:12 · answer #1 · answered by vlee1225 6 · 0⤊ 1⤋
to find the cost to cover, we need to find the area of the rectangular floor, which is 2(l+b)
Area = 2(40+50)
=2(90)
=180sq.ft
area of the square tile = 2*2=4sqft
no of tiles required to cover the floor=180/4 = 45
cost of 10 tiles = $13
cost of 45 tiles = (13/10)*45=$58.5
2007-08-01 16:23:59 · answer #2 · answered by jsm 2 · 0⤊ 0⤋
40 x 50 feet, but the tiles are 2x2, so it is 20 x 25 tiles.
20 * 25 = 500 tiles.
500 tiles / (10 tiles / package) = 50 packages.
50 packages * ($13 / package) = $650
2007-08-01 16:19:58 · answer #3 · answered by McFate 7 · 1⤊ 0⤋
do your own homework
2007-08-01 16:24:24 · answer #4 · answered by Dontugetit 3 · 0⤊ 1⤋
$650.00
2007-08-01 16:23:59 · answer #5 · answered by Will 2 · 0⤊ 0⤋