A frog fell into a hole that was 14 1/2 feet deep. He could jump 3 feet, but he slid back a foot each time he jumped. How many jumps does it take him to get out of the hole?
2007-08-01 15:55:09 · 16 answers · asked by ۞_ʞɾ_ 6 in Science & Mathematics ➔ Mathematics
It's actually only 7, because after the first 6 jumps he's 12 feet from the bottom (2 net ft. per jump, right?). So on the 7th jump he jumps 3 feet, getting to the 15ft mark and getting out of the hole, so he doesn't fall back a foot on the last jump.
2007-08-01 15:58:15 · answer #1 · answered by Cotton McKnight 3 · 0⤊ 0⤋
he's never going to get out of the hole. the hole is 14 1/2 feet deep, the first jump puts him up 3 feet off the floor of the hole, that's still 11 1/2 feet from the top. the next jump he slips down a foot and he can only jump to 121/2 feet from the top.
that little frog is doomed
2007-08-01 22:59:16 · answer #2 · answered by jOhAn 3 · 0⤊ 1⤋
The first jump landed him 11½ feet from the top. He slid back to 12½ feet. The second jump brought him to 9½ feet. He slid back to 10½ feet. The third jump, to 7½ feet. Each jump lands him two feet closer to his goal.
Continuing the series:
jump 3 ... 7½ feet
jump 4 ... 5½ feet
jump 5 ... 3½ feet
jump 6 ... 1½ feet
jump 7 ... out!!
2007-08-01 23:01:31 · answer #3 · answered by Boots McGraw 5 · 0⤊ 0⤋
8
2007-08-01 22:58:40 · answer #4 · answered by Tall Girl 3 · 0⤊ 1⤋
7 to 8
2007-08-01 22:58:15 · answer #5 · answered by Fighting Racoon 3 · 0⤊ 1⤋
8
2007-08-01 22:58:02 · answer #6 · answered by shay 3 · 0⤊ 1⤋
8
2007-08-01 22:57:46 · answer #7 · answered by princessgirlll 2 · 0⤊ 1⤋
8
2007-08-01 22:57:44 · answer #8 · answered by Anonymous · 0⤊ 1⤋
without sliding the frog can get out with for jumps without sliding each time. backing to ur question the frog can get out in 8 ummps. 8*3=24-8=16
2007-08-01 23:02:31 · answer #9 · answered by rb 2 · 0⤊ 0⤋
7 jumps since its 2 1/2 feet the last jump he souldn't slip back a foot
2007-08-01 23:06:44 · answer #10 · answered by betsy 1 · 0⤊ 0⤋