When 4.35 grams of silver metal are dropped in 1000. mL of 2.0 M acetic acid, how many liters of gas are evolved at STP?
can you help me without just giving the answers but showing the steps and reasons for each step?
2007-08-01 14:35:37 · 3 answers · asked by help 1 in Science & Mathematics ➔ Chemistry
Ag + HOAc >>> AgOAc + 1/2H2
First calculate moles of silver:
4.35g/107.9g/mol = 0.0403mole
From the equation, the ratio of Ag consumed to H atoms created is 1:1 but the ratio of silver consumed to hygrogen GAS (H2) created is 2:1. So, you will need a factor of 1/2 in the equation!
4.35g/107.9g/mol x 1/2 x 22.4L/mol = 0.452 liter
In case I'm losing you; let me explain this differently; if we reacted 1 atom of silver we would get 1 atom of hydrogen (or 1/2 a molecule) if we react 1 mole of silver, we would get 1 mole of "H atoms" which would actually be 1/2 mole of H2 gas or 11.2liters!
2007-08-01 15:22:53 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋
2 HOAc + 2 Ag = 2 AgOAc + H2
1.0 L of 2.0 M acid = 2 moles of HOAc
4.35 g of Ag x 1 mol / 107.9 g = 0.0403 mol
Clearly Ag is limiting
0.0403 mol Ag x 1 mol H2 / 2 mol Ag = 0.0806 mol H2.
0.0806 mol H2 x 22.4 L / mol = 1.806 L
2007-08-01 21:41:08 · answer #2 · answered by Fly On The Wall 7 · 0⤊ 0⤋
I doubt that acetic acid would disolve the silver at all.
It is a pretty weak acid you know.
2007-08-01 21:59:38 · answer #3 · answered by Irv S 7 · 0⤊ 0⤋