Prove the following formula:
Sin(pie/2 + Beta ) = cos beta
thank you
2007-08-01 14:25:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sin(A+B) = sinAcosB + cosAsinB
sin(pi/2) = 1
cos(pi/2) = 0
sin(pi/2 + beta)
= sin(pi/2)cos(beta) + cos(pi/2)sin(beta)
= 1*cos(beta) + 0*sin(beta)
= cos(beta)
2007-08-01 14:28:55 · answer #1 · answered by gudspeling 7 · 1⤊ 0⤋
sin(x+y) = sinx cosy+cosx siny
Sin(pi/2 + beta) = sin(pi/2) cos(beta)+cos(pi/2) sin(beta)
sin(pi/2) = 1 and cos(pi/2) = 0
Sin(pi/2+beta)=cos(beta)
2007-08-01 14:29:05 · answer #2 · answered by nyphdinmd 7 · 0⤊ 0⤋
sin(pi/2 + Beta )
= sin(pi/2)cos(Beta) + cos(pi/2)sin(Beta)
= cos(Beta)
2007-08-01 14:29:36 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
CHEATER! I am telling!
2007-08-01 14:32:12 · answer #4 · answered by Anonymous · 0⤊ 1⤋