2007-08-01 11:12:16 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2(X+4)=4(3X+2)
divide both side by 2
X+4 = 2(3X+2)
X+4=6X+4
add (-4) to both sides
X=6X
X=0
2007-08-01 11:24:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋
4(3x+2) = 2(x+4) cross mulitply
12x + 8 = 2x + 8 distribute
10x = 0
x = 0
2007-08-01 18:18:35 · answer #2 · answered by π∑∞∫questionqueen 3 · 0⤊ 0⤋
2 (x + 4) = 4 (3x + 2)
2x + 8 = 12x + 8
10x = 0
x = 0
2007-08-01 21:32:41 · answer #3 · answered by Como 7 · 0⤊ 0⤋
2(x+4) = 4(3x+2) - cross multiplying
2x+8 = 12x+8
10x = 0
x=0
2007-08-01 18:16:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2/(3x+2)=4/(x+4)
2 (x+4) = 4(3x+2)
2x + 8 = 12x + 8
2x - 12x = 8 - 8
-10x = 0
x = 0
2007-08-01 18:17:02 · answer #5 · answered by fofo m 3 · 0⤊ 0⤋
2(x+4)=4(3x+2)
x+4=6x+4
5x=0
x=0
2007-08-01 18:15:39 · answer #6 · answered by Anonymous · 0⤊ 0⤋
2(x+4)=4(3x+2)
2x+8=12x+8
0=10x
x=0
2007-08-01 18:15:32 · answer #7 · answered by jim 3 · 1⤊ 0⤋