If AB II CD and BC II AD, find m<1, m<2
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2007-08-01 08:11:34 · 6 answers · asked by Mike Gaol 1 in Science & Mathematics ➔ Mathematics
m<1 = 40 because <1 and the known 40 degree angle are opposite internal angles where parallel lines are crossed by a transveral, making them congruent.
m<2 = 75 because it <1 is an angle in a triangle where the other two angles are known to be 65 and (after we have calculated m<1) 40. The sum of all three angles in a triangles must be 180, so m<2 = 180 - (65 + 40) = 75.
2007-08-01 08:15:13 · answer #1 · answered by DavidK93 7 · 1⤊ 0⤋
1 = 40 and 2 = 75
2007-08-01 15:15:09 · answer #2 · answered by gfulton57 4 · 0⤊ 0⤋
<1=40*
<2=75*
<1- Alternate interior angles are equal.
<2- Add 65* and 40* to get 105*. Then subtract 105* from 180* to get 75*.
2007-08-01 15:16:39 · answer #3 · answered by JB 2000 1 · 0⤊ 0⤋
m<1=40
m<2=75
2007-08-01 15:18:12 · answer #4 · answered by dazed and confused 2 · 0⤊ 0⤋
<1 = 40 <2 = 75
i think...
2007-08-01 15:14:29 · answer #5 · answered by Anonymous · 0⤊ 0⤋
4^67
2007-08-01 15:14:00 · answer #6 · answered by QueenKoopa 4 · 0⤊ 0⤋