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What is the distance between A(-1, 2, 3) and B(4, -5, 6), rounded to the nearest tenth?

2007-08-01 07:37:29 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Standard distance formulas:

1 dimension:

√( (x1 - x2)² ) = | x1 - x2 |

2 dimensions:

√( (x1 - x2)² + (y1 - y2)² )

3 dimensions:

√( (x1 - x2)² + (y1 - y2)² + (z1 - z2)² )

= √( 5² + 7² + 3² )

= √(83)

approx: 9.11043358

rounded: 9.1

2007-08-01 07:43:54 · answer #1 · answered by сhееsеr1 7 · 0 0

two points: (x0,y0,z0) and (x1,y1,z1)

Distance is just SQRT(dx^2 + dy^2 + dz^2)
where dx= x1 - x0 and dy = y1 - y0 and dz = z1 - z0

here dx = 5 dy = -7 dz = 3

distance = sqrt(25 + 49 + 9) = sqrt(83)

2007-08-01 14:43:56 · answer #2 · answered by Captain Mephisto 7 · 1 0

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