1-(9z+2y) / (2z) + (9z - 4y) / (5z)
2007-08-01 06:46:56 · 5 answers · asked by Brandon 1 in Science & Mathematics ➔ Mathematics
1 - (9z+2y)/(2z) + (9z - 4y)/(5z)
Common denominator: 2*5*z = 10z
(10z/10z)*1 - (5)(9z+2y)/[5(2z)] + 2(9z - 4y/[2(5z)]
10z/10z - (45z+10y)/10z + (18z - 8y)/10z
(10z - 45z - 10y + 18z -8y)/(10z)
(-18y - 17z)/(10z)
2007-08-01 06:52:00 · answer #1 · answered by lockedjew 5 · 0⤊ 0⤋
1 - (- [9z + 2y] / 2z) + ([9z - 4y] / 5z)
10z/10z - (- [45z + 10y] / 10z) + ([18z - 8y] / 10z)
(73z - 18y) / 10z
Answer: (73z - 18y) / 10z
2007-08-05 00:29:07 · answer #2 · answered by Jun Agruda 7 · 2⤊ 0⤋
5(9z+2y)/10z+2(9z-4y)/10z=(45z+10y+18z-8y)/10z
=(63z+2y)/10z
2007-08-01 06:54:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
=(10z-45z-10y+18z-8y)/10z=(-17z-18y)10z
2007-08-01 06:52:08 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
get a calculator.
2007-08-01 06:51:13 · answer #5 · answered by Anonymous · 0⤊ 0⤋