2007-08-01 06:32:13 · 8 answers · asked by Jack L 1 in Science & Mathematics ➔ Mathematics
sqrt(8) + sqrt(18) - sqrt(32)
= sqrt(4*2) + sqrt(9*2) - sqrt(16*2)
= 2sqrt(2) + 3sqrt(2) - 4sqrt(2)
= (2+3-4)sqrt(2)
= sqrt(2)
2007-08-01 06:35:42 · answer #1 · answered by MsMath 7 · 1⤊ 1⤋
√2
2007-08-01 06:36:18 · answer #2 · answered by Dave 2 · 0⤊ 0⤋
= √8 + √18 - √32
= 2√2 + 3√2 - 4√2
= √2
2007-08-05 00:14:58 · answer #3 · answered by Como 7 · 0⤊ 0⤋
your question doesnt make sense in math terms. if x=9, 2(9)+7=5 18+7=5 25=/=5 doesnt equal. solving for x 2x+7=5 ....-7..-7 2x= -2 .÷2...÷2 x = -1 is 2x+7=5 all under a square root? i'd look at it again
2016-05-20 00:27:10 · answer #4 · answered by ermelinda 3 · 0⤊ 0⤋
square root of 8=2.82842712
square root of 18=4.24264069
square rrot of 32=5.65685425
2.82842712+4.24264069-5.65685425=1.41421356
answer is 1.41421356 or to 3 sig figs=1.41
might be wrong hope not
2007-08-01 06:38:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋
sqrt(8) + sqrt(18) - sqrt(32)
sqrt(4)*sqrt(2) + sqrt(9)*sqrt(2) - sqrt(16)*sqrt(2)
2sqrt(2) + 3 sqrt(2) - 4sqrt(2)
5sqrt(2) - 4sqrt(2)
sqrt(2)
2007-08-01 06:37:23 · answer #6 · answered by T 5 · 0⤊ 0⤋
sqrt(8)+sqrt(18)-sqrt32
=sqrt(2x2x2)+sqrt(2x3x3)-sqrt(2x2x2x2x2)
=2sqrt(2)+3sqrt(2)-4sqrt(2)
=sqrt(2)
2007-08-01 06:41:23 · answer #7 · answered by flori 4 · 0⤊ 0⤋
sqrt8=2sqrt2
sqrt18=3sqrt2
sqrt32=4sqrt2
so when you add and subtract as you've stated you get 1sqrt2 or simply sqrt2
2007-08-01 06:36:41 · answer #8 · answered by hrhbg 3 · 0⤊ 0⤋
1.414213562
2007-08-01 06:41:11 · answer #9 · answered by girl w/glasses 3 · 0⤊ 0⤋