Express as a single fraction in lowest terms
(2t-7y) / (3t) + (5t+9y) / (2t) +1
2007-08-01 05:24:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(2t-7y) / (3t) + (5t+9y) / (2t) +1
= [(2t-7y)/(3t)*(2t+1)/(2t+1)] +...
[(5t+9y)/(2t) +1* (3t/3t)] -->Get same denominator.
= [(2t-7y)(2t+1)/(3t)(2t+1)] + ...
[(5t+9y)(3t)/(2t+1)(3t)] -->FOIL it out on top & bottom, if ness.
= [(4t²+2t-14ty-7y)/(6t²+3t)] + ...
[(15t²+27ty)/(6t²+3t) --> Add together now.
= (4t²+15t²+27ty-14ty+2t-7y) / (6t²+3t)
= (19t² + 13ty + 2t - 7y) / [3t(2t+1)]
2007-08-01 05:36:50 · answer #1 · answered by Reese 4 · 0⤊ 0⤋
creating a single fraction requires the determination of a least common denominator.
An analysis of your expression yields a LCD of 6t.
Multiplying each term in the expression by 6t, produces the following:
4t-14y + 15t +27y +6t / 6t
combine like terms
25t + 13y / 6t
2007-08-01 12:45:25 · answer #2 · answered by Brian N 2 · 0⤊ 0⤋
(4t - 14y) / 6t + (15t + 27y) / 6t + 6t / 6t
(4t + 15t + 6t - 14y + 27y ) / 6t
(25t + 13y) / 6t
2007-08-05 06:52:59 · answer #3 · answered by Como 7 · 0⤊ 0⤋
(19t + 13y + 6)
/(6)
2007-08-01 13:04:20 · answer #4 · answered by Nardoff 2 · 0⤊ 0⤋