Find derivatives: Y=(x+1/X-2) 2 ..........tnx guys!!!!!?

Answer 1

I assume that the 2 at the back is an exponent. The quotient is squared. ©

D(x+1/x-2)² = 2(x+1/x-2) * [(x-2)-(x+1)]/(x-2)²
= -6(x+1)/(x-2)³

Do the power rule before the quotient rule.

Answer 2

Too ambiguious. If x the same as X?. What is the "2"; if a square, put "^" in front of it. You been on this answer section enough to know better.

Answer 3

If y=f(x)^2 -> y'=2f(x)f'(x)

Let f(x)=(x+1)/(x-2)
Then
f'(x) = [(x - 2) - (x + 1)]/(x - 2)^2 = -3/(x - 2)^2

y' = 2f(x)f'(x) = 2(x+1)/(x-2) * (-3)/(x-2)^3 =
= -6(x+1)/(x-2)^3