For 2y+10=0, if you solve for y, the line is y= -5 . This line intercept the y axis at y= -5. It's a horizontal line!! It NEVER intercepts with the x axis.
You do the same thing for 3x+12=0. This line is verticle. If you solve for x, you'll see that it never intercepts the y axis!
2007-08-01 01:06:46
·
answer #1
·
answered by Anonymous
·
3⤊
0⤋
1)
2y + 10 = 0
2y = -10
y = -5
Whatever (y) = is the y intercept.
2)
3x + 12 = 0
3x = - 12
x = -4
Whatever (x) = is the x intercept.
In your two problems, they only gave you one variable each. Usually, you will have an (x) and a (y) in each problem. To find the intercepts, you give x the value of 0 to find the y intercept. You give y the value of o to find the x intercept.
An intercept is where the graph of the line crosses the x or the y axis on a coordinate plane.
2007-08-01 01:02:40
·
answer #2
·
answered by Anonymous
·
1⤊
0⤋
2y + 10 =0
2y = -10
y = -5 A horizontal line that intercepts the y-axis at (-5)
3x + 12 = 0
3x = -12
x = - 4 A vertical line that intercepts the x-axis at (-4)
2007-08-01 01:02:22
·
answer #3
·
answered by tigamilla 2
·
1⤊
0⤋
2y+10= 0
2y= 0-10
2y= -10
y= -10/2
y= - 5
3x+12= 0
3x= 0-12
3x= -12
x= -12/3
x= -4
substitute x and y in their places and you will get the same answers.
2007-08-01 01:02:27
·
answer #4
·
answered by cute little 1
·
1⤊
0⤋
2y = - 10
y = - 5 is the y intercept
no x intercept
3x = - 12
x = - 4 is the x intercept
no y intercept
2007-08-01 14:41:02
·
answer #5
·
answered by Como 7
·
0⤊
0⤋
2y + 10 = 0
2y = -10
y = -5
Therefore,
y-interception = (0,-5)
3x + 12 = 0
3x = -12
x = -4
Therefore,
x-interception = (-4,0)
2007-08-01 01:57:55
·
answer #6
·
answered by Carrot 3
·
1⤊
0⤋
you do not even particularly might desire to placed it into slope intercept variety different than to make issues much less difficult for you yet to unravel for the y-intercept you will possibly desire to plug 0 in for x and resolve the equation for y...i like algebra so i'm the guy to ask!
2016-10-13 08:15:41
·
answer #7
·
answered by ? 4
·
0⤊
0⤋
For 2y+10=0
x= -10 y=-5 (10,-5)
For 3x+12=0
x=-4 y=-12
IF I REMEMBER RIGHT (CUZ DURING THE SUMMER I FORGET) THAT SHOULD PROBABLY BE CLOSE! if you have a calculator put it on the graph, hope i helped!
2007-08-01 01:11:49
·
answer #8
·
answered by p4e7ac7he1z 2
·
0⤊
0⤋
2y + 10 = 0
i.e. y = -5
3x + 12 = 0
x = -4
x-intercept = -4
y-intercept = -5
2007-08-01 01:03:49
·
answer #9
·
answered by Anonymous
·
1⤊
0⤋
2y+10=0
2y=-10
y=-10/2=-5
3x+12=0
3x=-12
x=-12/3=-4
verification
2X-5+10=0
-10+10=0
0=0
3x+12=0
3X-4+12=0
-12+12=0
0=0
2007-08-01 01:17:13
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋