this question was asked in my halfyearly.
my answer was u= -nv
2007-07-31 22:28:28 · 5 answers · asked by VICKY 1 in Science & Mathematics ➔ Physics
the formula for that is..
1/f(focal length)=1/do(distance of the object)=1/di(distance of image)
2007-07-31 22:41:02 · answer #1 · answered by jheanne e 1 · 0⤊ 2⤋
1/u + 1/v = 1/f gives 1/u -- 1/v = --1/f
also object : image = n : 1 giving u/v = n or v = u/n
then 1/u -- n/u = -1/f
or (n -- 1)/u = 1/f
whence u = (n -- 1)f
object distance is (n --1) times focal length f.
2007-07-31 22:51:39 · answer #2 · answered by sv 7 · 1⤊ 0⤋
Magnification = size of image/size of object
. . . . . . . . . . . = Image size / object size = (ob/n)/ob) = 1/n
Also, magnification = Dist. of image / Dist. of object
. . . . . . . .. . . . . . . 1/n = v / u
In the case of convex mirror image is always virtual, and hence treated as -ve.
. . . . . . . . . . . . . .1/n = -v / u
. . . . . . . . . . . . . . . -nv = u
The distance of the object is "n" times the distance of image.
-ve sign indicates that the image is virtual and is formed behind the mirror.
2007-07-31 22:55:34 · answer #3 · answered by Joymash 6 · 0⤊ 0⤋
according to the formula in the link
1/f = 1/d0+1/di and M=-di/d0 where M = magnification
so di = -M*d0 in your problem M=1/n and di =-d0/n
so 1/f = 1/d0 - n/d0= n-1/d0
d0= f/(1-n)
check with your notation . there are different formula with other letters
2007-07-31 22:53:39 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
If m = -2, then doesn't di = -2do? This would make the do = f/2
2016-04-01 05:12:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋