maht challenging sum?

Question

here is the sum.

there are two tap,a and b,tap a can fill up a bucket in 5 minutes and tap b can fill up the same buckets in 6 minutes,how long does it take for the two taps to fill up the bucket together.

i wrote maths wrongly.

well,my answer is 2min 40sec,i don't know if it is right,because i only do the rough working and i didn't calculate properly, please i really need the answer for this question.thanks very much,thank you,thank you,thank you,thank you,thank you,thank you,thank you,thank you,thank you, thank you, thank you,thank you,thank you,thank you,thank you.

Answer 1

let the volume of the bucket be V
Now tap a fills the bucket in 5 mins
hence, speed of a = V/5 volume per min
similarly speed of b = V/6 volume per min

Now if they take time T to fill the same bucket then
(V/5+V/6)=V/T
Hence, T= 30V/11V
T=30/11
T=2.7 mins

Answer 2

The time spent in thanking us can be better spent in learning maths!

Time taken for tap a to fill the bucket = 5 minutes

Time taken for tap b to fill the bucket = 6 minutes

Time taken for taps a and b to fill the same bucket = T

Now, the formula is 1/T = 1/5 + 1/6

= 11/30

So, T = 30/11 = 2 hrs and 43 minutes and 38.18 secs.

Answer 3

a can fill the bucket in 5 min
b can fill the bucket in 6 min
Therefore if they work together, every minute 1/5 + 1/6 of the bucket is filled.
1/5 + 1/6 = 11/30
11/30(1st minute)
22/30(2nd minute)
1- 22/30 = 8/30 (unfilled portion after 2mins)
1min = 60 sec
11 parts per 60 sec
8 parts per 43, 7/11seconds
Therefore the answer is 2 min, 43, 7/11 seconds

Answer 4

you first calculate the speed of each tap, as in second:

tap a fills the bucket in 5 minutes, which is 300 seconds, so it's speed is 1/300th of the bucket in every second.
tap b fills the bucket in 6 minutes, which is 360 seconds, so it's speed is 1/360th of the bucket in every second.

now add the two : you get 1/300 + 1/360 = 11/1800 of the bucket is filled in every second, using both taps.

so now that you have the speed, you know in every second 11/1800th of the bucket is filled, then you just need to know how man 11/1800th is equal to one, meaning the bucket is full.
therefore: x * (11/1800th) = 1
so x = 1800/11 = 163.3636363636....seconds.

Answer 5

*In 1 minute:
-Tap A can fill up 1/5 of the bucket
-Tap B can fill up 1/6 of the bucket
In 1 minute,the 2 taps can fill up together 1/5+1/6=11/30 of the bucket
1 minute--->11/30 bucket
X minute--->1 bucket
X=(1*1)/(11/30)=30/11 minutes~ 2.73 minutes
*check it:(30/11)*(1/5)+(30/11)*(1/6)=1
Hope it help you!!!

Answer 6

Let x = no. of minutes to fill a bucket

x/5 + x/6 = 1
6x/30 + 5x/30 = 1
11x/30 = 1
11x = 30
x = 30/11 min OR 2 8/11 min OR 2 min & 43 7/11 sec

Answer: 2 minutes & 43 7/11 seconds

Answer 7

I got 2 minutes and 43 seconds.

My method is:

1/5 +1/6 = 11/30

And then get the reciprocal of 11/30 which is simply 30/11 and then do the obvious mixed numbers, find # of seconds (since you're dealing with time) with percent stuff lol.

Answer 8

1/ x = 1/5 + 1/6

x = 30/11 = 2.73 min. you're roughly correct

Answer 9

x/5 + x/6 = 1

answer: 2.72727272 minutes or 2 minutes and 43.636 secs.

Answer 10

2.727 mins or 2 mins and 43.62 sec