I suggest the following "elementary proof": of course You know that
(a - b)(a + b) = a^2 - b^2 /a, b - arbitrary/, so we have:
(a - a)(a + a) = a^2 - a^2;
(a - a)(a + a) = (a - a)a;
a + a = a;
2a = a;
2 = 1, Quod Errat Demonstrandum!!!
The work for You to do is to find the bug in the above "proof".
So, enjoy!
2007-07-31 21:26:21
·
answer #1
·
answered by Duke 7
·
0⤊
0⤋
See the link below.
You could also say that 2 cups = 1 pint, although I don't that kind of argument.
Assuming that the numbers are the same unit, which I believe you can, there is no valid way to prove they are equal.
2007-07-31 21:06:04
·
answer #2
·
answered by Michael M 6
·
0⤊
0⤋
Well, lets take 2 halves of a hamburger. If I eat both halves I will still have eaten 1 whole hamburger. So in this case 2 = 1.
And it was a mighty good burger.
2007-07-31 21:02:21
·
answer #3
·
answered by Onerom 3
·
0⤊
0⤋
You can "prove" it using complex numbers.
1.) 1/-1 = -1/1
2.) sqrt (1/-1) = sqrt (-1/1)
3.) etc..
2007-07-31 21:10:40
·
answer #4
·
answered by mnial 3
·
0⤊
0⤋
http://mcraefamily.com/MathHelp/JokeProofFactoring.htm
Although there is a problem in its logic so it's not really true. Then again math humor is...uh...sparse so you take what you can get.
2007-07-31 21:05:43
·
answer #5
·
answered by J.T. 3
·
0⤊
0⤋
how can they be equal,they are two different numbers,
2007-07-31 22:19:29
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
http://mathforum.org/dr.math/faq/faq.false.proof.html
Just another reason why math is stupid.....
2007-07-31 21:07:28
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋