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evaluate i^i?

complex number question

2007-07-31 20:56:21 · 2 answers · asked by uncletimrob 2 in Science & Mathematics ➔ Mathematics

2 answers

i^i = e^(i lni)
ln i = ln (e^(πi/2)) = πi/2

i^i = e^(i*πi/2) = e^(-π/2) = 0.2079
©

2007-07-31 21:06:08 · answer #1 · answered by Alam Ko Iyan 7 · 0⤊ 0⤋

e^(-PI/2)

2007-07-31 20:59:31 · answer #2 · answered by Michael M 6 · 0⤊ 0⤋

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