5x^2+7x+1=0
2007-07-31 19:44:23 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = [ - 7 ± √(49 - 20) ] /10
x = [- 7 ± √29 ] /10
x = - 0.161 , x = - 1.24
2007-07-31 21:09:47 · answer #1 · answered by Como 7 · 0⤊ 0⤋
5x^2+7x+1=0
let,
a=5,
b=7 &
c=1
now put these values in the formulae-
for 1st value of x
x= {-b+(b^2-4ac)^1/2}/2a
&,for 2nd value of x
x={-b-(b^2-4ac)^1/2}/2a
on solving
the 1st value of x will be,
x={-7+(29)^1/2}/10=-0.162
&,its 2nd value will be,
x={-7-(29)^1/2}/10=-1.238
2007-08-01 06:04:08 · answer #2 · answered by ayush 1 · 0⤊ 0⤋
from ax²+bx+c = 0 ..... ©
x = [-b ± â(b²-4ac)] / 2a
x = [-7 ± â(49-20)] / 10
x = [-7 ± â(29)] / 10
2007-08-01 03:50:48 · answer #3 · answered by Alam Ko Iyan 7 · 1⤊ 1⤋
x = -0.16148 and -1.2385
have a nice day!! (i stole this answer from cherry passion :-P) i love u chezza!
2007-08-01 03:48:34 · answer #4 · answered by Wholetail Scampi 2 · 0⤊ 0⤋
x = -0.16148 and -1.2385
2007-08-01 02:49:32 · answer #5 · answered by cherrypassion 2 · 0⤊ 0⤋