English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

For example, I used Maple to find the roots of:
(r^4 + 5r^2 +4=0). How do you find the roots by hand? thanks

2007-07-31 19:14:06 · 5 answers · asked by thatguy2007 2 in Science & Mathematics Mathematics

5 answers

Note that all powers of r in the given equation are even.

Let x = r^2. This will reduce he equation to a quadratic equation which you can solve by factorization.

x^2 + 5x + 4 = 0
(x+4)(x+1)=0
x={-4, -1}

r = ±sqrt(x)
r = {-2i, -i, i, 2i}

2007-07-31 19:17:27 · answer #1 · answered by gudspeling 7 · 1 0

Do the following:
Consider that r^2=x.
Your ecuation will now be x^2 +5x +4 =0, with the roots -1 and -4, if i'm not mistaken.
Now, reverting to your previous notations, you have r^2 = -1 and r^2=-4.
r^2 = -1 leads to r = +i and -i
r^2 = -4 leads to r=sqrt(-4)= sqrt(-1) x sqrt(4)= +2i or -2i.
I hope this clears things up. Feel free to contact me for more questions

2007-08-01 02:50:04 · answer #2 · answered by Shadow 3 · 0 0

r ² = [ - 5 ± √(25 - 16) ] / 2
r ² = [ - 5 ± 3 ] / 2
r ² = - 1 , r ² = - 4
r ² = i ² , r² = 4 i ²
r = ± i , r = ± 2i

2007-08-01 03:00:24 · answer #3 · answered by Como 7 · 0 0

guess and check theres no other way to find complex roots by hand unless you know the exponent opposite

2007-08-01 02:17:10 · answer #4 · answered by trev 2 · 0 2

math.com

2007-08-01 02:15:59 · answer #5 · answered by bimmer boy 2 · 0 0

fedest.com, questions and answers