Did you try page 107 from Universe in a Nutshell by Stephen Hawking? I think you will find the rest of the equation there.
Ψ(bar, sub 0) = √(m/π)*e^(-2α(xbarsubi)² + A)
where xbarsubi is x bar(mean value) sub 'i'
Not sure how that wil help you, and that's too advanced for me right now(it's on a picture, so really no details about it)....
2007-07-31 20:35:23
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answer #1
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answered by Daniel 4
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Not that it really matters, given the obviously incomplete nature of this equation, but it starts out with the complex conjugate of some given or previously derived wave function.
The subscript "o" seems to indicate that this is a basis wave function, possibly being established prior to some further perturbation expansion.
Live long and prosper.
NOTE to both Kenny B and lithiumdeuteride: There's no indication that ' m ' is a mass. It could be an angular quantum number required in the normalization.
2007-07-31 19:26:02
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answer #2
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answered by Dr Spock 6
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Unless there is another term with units of 1/sqrt(m) later on, the equation is inherently non-physical. Since the left side is a wave function (inherently unitless), the right side must also be unitless.
All I can see is a sqrt(m) term, which would have units of kilograms to the 1/2 power, which cannot exist. So without being able to see the full equation, all I can say is that the visible part is gibberish and means nothing.
2007-07-31 19:32:21
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answer #3
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answered by lithiumdeuteride 7
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I can't really make out the entire equation, but what you are looking at there is a wave function, which is the the solution to Schrodinger's Equation for Quantum Mechanics (QM). In QM, particles and waves are explained by a wave function, this one here in particular (though I can see the exponential) seems to be an exponential wave function which is a consequence of the type of potential it finds itself in. The square root sign in front with an "m/pi" is simply the normalization constant. The wave function, when squared, is proportional to the probability of finding a particle in a certain state. Hope this helps - if you need further clarification please ask. Thanks for asking.
2007-07-31 18:56:59
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answer #4
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answered by brix510 4
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It looks like the ground state of an electron in a hydrogen atom, but the 'm' is the wrong order. However, the remaining part of the equation (which cannot be seen) may rectify this.
There is nothing to solve here. This is the solution to a problem involving the Schrodinger equation.
2007-07-31 19:02:07
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answer #5
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answered by Anonymous
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properly, it actual relies upon: once you're a Ph.D. Physicist ---> Then probable no longer a heck of plenty better than you ought to already be responsive to or have studied. once you're a lay guy or woman ---> Then i could say i will inform you adequate to fill a superb-length library [and that's basically stuff off the genuine of my head.... :-) ]. right this is slightly suggestion, if i'm going to. while you're no longer certainly committed to transforming into a physicist, a chemist, an electric powered engineer, or a logician of technology, then my suggestion to you would be: stay your existence classically, and you may hardly ought to be conscious any quantum mechanical consequences, by any potential! If on the different hand, you're in college an are forced to take a direction, or you're basically inquisitive approximately it, then google it and initiate up getting on the countless many web pages committed to the priority (from the main undemanding to even the improvement stages) and/or bypass to the college library and artwork your way up from there. do you have to be clever adequate, you will no longer even prefer everybody to teach you Q.M. - with a superb little bit of dedication and adequate brains to examine it, you may fairly %. it up on your guy or woman.
2016-11-10 21:24:13
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answer #6
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answered by ? 4
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