Can Someone Please Help Me With These Two Math Problems???

Question

1.) The measures of the anlges of a triangle in the ratio 3: 3: 4. Find the measure of each angle.

2. Prove: If a diagonal of a prallelogram bisects an angle of the parallelogram, the parallelogram is a rhombus. (State plan and give proof)

Given: ABCD is a parallelogram with angle 1 congruent to angle 2

To Prove: ABCD is a rhombus

(Can you plase help me with the statements and the reasons for the proof)

Answer 1

1) 54, 54, and 72

Answer 2

1) Three angles of a triangle total 180 degrees.
Proportions 3, 3, 4 add up to 10
Divide 180 by 10, gives 18.
3 x 18 = 54, 4 x 18 = 72.
Proof: 54 + 54 + 72 = 180

2) Opposite angles of a parallelogram are congruent.
The diagonal will also form two congruent triangles.
Angles on the diagonal base are proportional,
to the opposite sides of the formed trianges.
If the diagonal bisects the parallelogram angles,
then all 4 internal angles must be equal.
Therefore the sides of the triangle are equal.
Which makes the parallelogram a rhombus.