English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

why doesnt the dilution of the buffer (NaOH and acetic acid) not change the pH of the buffer by very much..why not?

why isnt deionized water not likely to have a pH of 7 ?

compare the change in pH with the addition of acid and base to deionized water and to your buffer. explain the difference

2007-07-31 16:58:33 · 3 answers · asked by Sean H 1 in Science & Mathematics Chemistry

3 answers

For the first part of your question: A buffer's job is to keep a steady pH in a system. For instance, our bodies have many buffer systems (think carbonic acid) that keep our bodies at around the same pH(slightly acidic). If you add water(to dilute it), the water will react with the acid which inturn will be equalized by the salt. I believe this is right....

For the second part, ionized water is highly reactive and will tear other water molcules apart. Hydonium, for example is a weak acid(that is ionized water), so it would have a low pH.

third part: addition of acid would just make it more acidic, no reaction. Reaction of Base would led to going neutral and then basic. Add acid or base to the buffer, there will be no change untill the buffer can handle no more, then the pH will fluctuate.

Sorry if some of this is just totally wrong...tired.

2007-07-31 17:24:20 · answer #1 · answered by Anonymous · 0 0

Leave it alone, do not buffer, do a water change with RODi water , or do not leave the lights on as long. The longer the lights are on the higher the PH will go. Ph stability is much more important than the actual level, as long as the level is between 7.8 to 8.4. Never try to buffer PH in the tank, instead check and buffer alkalinity as needed.

2016-05-19 03:42:57 · answer #2 · answered by ? 3 · 0 0

A buffer solution is made with both a weak acid(or base) dissolved in water with a alkaline salt(or halide salt). The solution resists changes in pH by (for the weak acid/salt case) converting strong acid to weak acid (reaction with the salt) or converting strong base to salt (reaction with the acid).

You have a double negative here, so I don't know what you are asking.

2007-07-31 17:25:18 · answer #3 · answered by cattbarf 7 · 0 0

fedest.com, questions and answers