0
10
1110
3110
132110
1113122110
311311222110
(3 ones, 1 three, 1 one, 2 twos, 2 ones, 1 zero)
2007-07-31 15:12:08
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answer #1
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answered by gudspeling 7
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zero is comprised of a digit, which is '0'. Therefore for the second number, there is 1 '0', which makes 10. There is 1'1' digit and 1 '0' digit in 10 and therefore for the third number you get 1110. Continue on and after you get 1113122110, you get 311311222110.
2007-07-31 21:30:46
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answer #2
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answered by Anonymous
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311311222110
You're literally just describing the number before each one. Like three number ones, one number three...
2007-07-31 15:18:56
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answer #3
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answered by Dill 4
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It is
311311222110
This is Conway's famous "look-say" sequence.
2007-07-31 15:26:46
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answer #4
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answered by steiner1745 7
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311311222110
2013-10-14 21:27:56
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answer #5
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answered by Shirish K 1
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it can either be 311311222110 or 11,111,112,111,212,111,110
2007-07-31 15:14:47
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answer #6
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answered by 7
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