a^2 - 64 = 0 please help me solve it and express irrational solutions in simplest radical form. thanks?

Question

a^2 - 64 = 0

Answer 1

(a - 8) (a + 8) = 0
a = 8 , a = - 8

Answer 2

This problem has only rational solutions, so we don't have to sweat the heavy stuff.

a^2 -64 = 0
a^2 = 64
a = + or - 8
Whenever you take a square root of a number, you always get two answers: a + answer and a - answer.
Makes sense: after all a + times a + = +, and a -
times a - also = +
You should substitute your answers back into the original equation to make sure both answers are acceptable. In this problem they both are.
Good luck.

Answer 3

First isolate the variable:

a^2 - 64 = 0
a^2 = 64

Now square root both sides:

a = sqrt(64)
a = 8

Ah! Remember that it's both positive and negative:

a = 8, -8

Answer 4

Hi,

For this question, you first need to add 64 to both sides of the equation to get the following:

a^2 = 64

Then, you need to take the square root of both sides of the equation. However, remember that the square root of a number leaves you with a plus / minus solution. This is so because when you multipyl two negative numbers together, you get a positive just like when you multiply two positive numbers together to get a positive.

Therefore, your final answer for this question is 8 and -8.

I hope that helps you out! Please let me know if you have any other questions!

Sincerely,

Andrew

Answer 5

1) a^2 - 64 = 0
2) rearrange the equation to a^2 = 64
3) take the square root of both sides (a^2)^(1/2) = (64)^(1/2)
4) solving using a calculator if you can't do it in your head, a = +/- 8

Answer 6

ln(x+4) - ln(x+3) = lnx ? Condense the left area making use of log regulations ? ln((x+4) / (x+3)) = lnx ? Exponentiate the two aspects to cancel the logs ? e^ln((x+4) / (x+3)) = e^lnx (x+4) / (x+3) = x x + 4 = x(x+3) x+4 = x² + 3x 0 = x² + 2x - 4 4 = x² + 2x ? finished the sq., it somewhat is much less difficult to tutor on right here than the quadratic formulation. the two will internet you an identical solutions. it somewhat is very own determination ? 4 + a million = x² + 2x + a million 5 = (x+a million)² ±?5 = x + a million -a million ± ?5 = x x = -a million + ?5 x = -a million - ?5 <-- This answer is extraneous because of the fact it makes ln(x) not exist because of the fact it somewhat is unfavorable x = -a million + ?5 <-- in undemanding terms answer

Answer 7

a^2 - 64 = 0 factor out your equation

(a+8)(a-8) take each parenthesis, set = to 0 and solve for a

a+8=0 subtract 8 from both sides
a+8(-8)=0+(-8) simplify
a= -8

a-8=0 add 7 to both sides
a-8(+8)=0+(+8) simplify
a=8

so your answers are a=8 & -8

Answer 8

a^2-64
=a^2-(8)^2
=(a-8)(a+8)
so a=8 or -8 ans
Otherway you can do it like
a^2=64=8^2
or a=+-8 ans

Answer 9

so lets factor this

a^2-64=(a-8)(a+8)=0 so a=8 or a=-8

Answer 10

a^2-64=0
a^2=64
a=+-8 [square rooting both sides]