simplify question 1) -5x^(-1) + 2y^(-1) over 9x^(-2) -7y^(-2) question 2) (1/x+2)+(4/x-3) over (2/x-3)-(7/x+2) solve the equation question3) (4/x+5)-(6/x-5)=(2/x^2-25) question 4) (8/2x^2+8x)=1-(1/x+4)
2007-07-31 10:47:49 · 4 answers · asked by Jim 2 in Science & Mathematics ➔ Mathematics
{-5x^(-1)+2y^(-1)}/{9x^(-2)-7y^(-2)}
or {-5/x+2/y}/{9/x^2-7/y^2}
or {(2x-5y)/xy}{(9y^2-7x^2)/x^2y^2}
or (2x-5y)(9y^2-7x^2)/x^3y^3 ans
2007-07-31 11:06:36 · answer #1 · answered by MAHAANIM07 4 · 0⤊ 0⤋
If you are saying that only the x is raised by the ^-1 or -2:
Then this means: x^-1 = 1/x, OR
x^-2 = 1/x²
1. [-5x^(-1) + 2y^(-1)] / [9x^(-2) -7y^(-2)]
[-5/x + 2/y] / [9/x² - 7/y²]
...that should get you started.
For the rest, factor if necessary, get a common denominator, then solve.
2007-07-31 17:57:07 · answer #2 · answered by Reese 4 · 0⤊ 0⤋
Too many questions, Jimmy. This makes us feel like we're doing your homework for you.
Submit one question, see how it's done, and see if that helps you with the other 3.
2007-07-31 17:53:56 · answer #3 · answered by whabtbob 6 · 0⤊ 0⤋
who would know how to answer this question???
2007-07-31 17:54:00 · answer #4 · answered by ? 2 · 0⤊ 0⤋