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q(x)= ln(x+3) - ln(x-5)

2007-07-31 09:02:15 · 2 answers · asked by c 1 in Science & Mathematics Mathematics

2 answers

q(x) = ln[(x + 3)/(x - 5)]

Switch q and x, and find q again in terms of x.

x = ln[(q + 3)/(q - 5)]

e^x = (q + 3)/(q - 5)

qe^x - 5e^x = q + 3

q(x) = (3 + 5e^x)/(e^x - 1)

2007-07-31 09:08:16 · answer #1 · answered by Anonymous · 0 0

y= ln[(x+3)/(x-5)]

so e^y = (x+3)/(x-5) so x e^y -5 e^y = x+3
x(e^y-1)= 5e^y+3
x= (5e^y+3)/(e^y-1)

interchange x and y
y=(5e^x+3)/(e^x-1)

2007-07-31 09:11:01 · answer #2 · answered by santmann2002 7 · 0 0

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