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a. [6]-annulene
b. [14]-annulene
c. [16]-annulene
d. [18]-annulene

2007-07-31 08:10:44 · 4 answers · asked by dave b 2 in Science & Mathematics Chemistry

4 answers

[14]-annulene and [18]-annulene are aromatic as well as [6]-annulene which is benzene. They all obey Huckels 4n+2 rule for aromaticity. [16]-annulene does not obey Huckels rule and would therefore not be aromatic.

2007-07-31 09:08:15 · answer #1 · answered by Anonymous · 0 0

Its forsure not annulene 16 b/c it doesn't have a Huckel(4n+2) number of electrons. However I'm about to take a organic 2 test and stumbled upon a curve ball thats messing me up in regards to aromaticity. My book says annulene ten isn't aromatic because the hydrogen atoms on the inside of the ring exhibit steric hinderance and therefore can't adopt a planar formation to have a continously overlapping P orbital and for a similar reason annulene 14 is somewhat destabilized and non planar making it nonaromtic.

2015-02-25 07:54:05 · answer #2 · answered by Hunter 1 · 0 0

Annulene

2016-09-30 01:35:02 · answer #3 · answered by ? 4 · 0 0

The 16 one. It does not fit the rule.

2007-07-31 08:24:14 · answer #4 · answered by Gervald F 7 · 0 0

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