What is the equation of a circle with radius 9 and center (-2,3)?

Question

If you could please explain how you got your answer, I would appreciate it. :)

Answer 1

equation of a circle with radius r and center (h, k) is

(x-h)^2 + (y-k)^2 = r^2.


(x+2)^2 + (y-3)^2 = 9^2

Answer 2

The equation of a circle with the center at the origin of a (x,y)coordinate system is x^2 + y^2 = r^2. The center that you show is ( -2, 3) These are translation points that move the center of the circle to some point other than (0,0). They are usually denoted as ( h,k) So all you have to do is place them in the equation (x-h)^2 + ( y-k) ^2 = r^2 The equation becomes (x+2)^2 + ( y-3)^2 = 9^2 Remember that -(-2) is +2

Answer 3

The equation of a circle is given by the equation:
(x-a)^2 + (y-b)^2 = r^2 where the center is (a,b) and the radius is r.
So the equation is (x-(-2))^2 + (y-3)^2 = 9^2
=>
(x+2)^2 + (y-3)^2 = 81.

Answer 4

In general, circle equations always follow the same pattern:

(x-h)^2+(y-k)^2=r^2

where r is the radius and (h,k) is the center.

So for you, the correct equation would be (x+2)^2+(y-3)^2=81.

Answer 5

I don't understand if you want the raidus or the circumfrince so I will show the equasion for both.
circumfrince Diameter
9x3.14=28.26 9x2=18

the equasion for circumfrince is
raidus x pie= cir

Answer 6

Saying the equation wouldn't be the answer so I wouldn't know....Im thinking.....12, final answer.

Answer 7

81=(x+2)^2 + (y-3)^2

Answer 8

if i remember correctly I think its

0=(3y+2)^2 + ( 3x-3)^2

Answer 9

SUGAR