find a formula for the function?

1 ⤊

let k(x) = x^2 and n(x) = (2x^2)/(x+1)

find k(n(x))

2007-07-31 05:00:50 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

k(n(x)) = (2x^2 / (x+1))^2
= 4x^4 / (x+1)^2

2007-08-04 03:43:39 · answer #1 · answered by robert 6 · 0⤊ 0⤋

k(n(x)) = [(2x^2)/(x+1)]^2 = 4x^4/(x+1)^2

2007-07-31 12:09:53 · answer #2 · answered by ironduke8159 7 · 1⤊ 0⤋

plug in (2x^2)/(x+1) in place of x for k(x)

[(2x^2)/(x+1)]^2
f(n(x)) = 4x^4/(x+1)^2

2007-07-31 12:07:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋