can someone please help me with this hoework question.. its due 2day please helpp?

Question

A car is traveling along a straight road at a velocity of +37.0 m/s when its engine cuts out. For the next ten seconds, the car slows down, and its average acceleration is 1. For the next five seconds, the car slows down further, and its average acceleration is 2. The velocity of the car at the end of the fifteen-second period is +20.6 m/s. The ratio of the average acceleration values is 1/2 = 1.52. Find the velocity of the car at the end of the initial ten-second interval.
__m/s

Answer 1

Sorry. If the car is slowing down, its acceleration will be negative, not positive. Do you mean "its average acceleration is -1 m/s^2" (or "its deceleration is 1 m/s^2")? The same question applies to the 5-second interval that follows.

You will probably get a prompt response if you add a comment clarifying this.

Answer 2

37 - 10(1.) - 5(2.) = 20.6
16.4 = 10(1.) + 5(2.)

(1.)/(2.) = 1.52
(1.)/1.52 = (2.)

10(1.) + 5((1.)/1.52) = 16.4
(1.) x (10 + 5/1.52) = 16.4
(1.) x (10 + 3.29) = 16.4
(1.) x (13.29) = 16.4
(1.) = 1.23

37 - 10 x 1.23 = 24.7 m/s