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Question

In /\ABC, a line drawn from vertex A intersects BC in D. If m

Answer 1

6x +9x-45 = 180 { 15x = 225
x = 15
Thus Therefore < ADB is a right angle {by definition}
Therefore AD _|_ BC {by definition}

Answer 2

If
m
6x + 9x -45 = 180
15x = 225
x = 15

Substitute x into the angle measures:

m
m
Since the definition of perpendicular lines is that they intersect at a 90 deg angle, it has been shown.

Answer 3

Since < ADB and < ADC are co-linear,

6X + 9x - 45 = 180
15x = 180 + 45
15x = 225

x = 225/15 = 15

Glad to help....

therefore m < ADB = 6X = 6*15 = 90 deg
and m < ADC = 9X - 45 = 9*15 - 45 = 135 - 45 = 90 deg

that proves that AD _|_ BC

Answer 4

angle adb + angle adc = 180 since they'll form a straight line. Thus,

6x + 9x - 45 = 90
15x - 45 = 90 (combine like terms)

Solve for x: x = 15

Substitute the value of x to angle adb and angle adc, you'll get 90 to both measures of angle. Therefore, line segment AD is perpendicular to line BC since it formed two right angles.